Pitomath
Anonymous
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- asked 4 months agoVotes
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Giải SBT Toán 8 Bài 5: Phép cộng các phân thức đại số
a) 1−2x6x3y+ 3+ 2y6x3y+ 2x−46x3y;
b) x2−2x(x−1)2+2−xx(x−1)2;
c) 3x+ 1x2−3x+ 1+ x2−6xx2−3x+ 1;
d) x2+38x+ 42x2+ 17x+ 1+ 3x2−4x−22x2+ 17x+ 1 .
a)
1−2x6x3y+ 3+ 2y6x3y+ 2x−46x3y=1−2x+3+2y+2x−46x3y=2y6x3y=13x3
b)
x2−2x(x−1)2+2−xx(x−1)2=x2−2+2−xx(x−1)2=x2−xx(x−1)2=x(x−1)x(x−1)2=1x−1
c)
3x+ 1x2−3x+ 1+ x2−6xx2−3x+ 1=3x+ 1+ x2−6xx2−3x+ 1=x2−3x+ 1x2−3x+ 1=1
d)
x2+38x+ 42x2+ 17x+ 1+ 3x2−4x−22x2+ 17x+ 1= x2+ 38x+ 4+ 3x2−4x−22x2+ 17x+ 1
=4x2+34x+ 22x2+ 17x+ 1=2.2x2+ 17x+ 12x2+ 17x+ 1=2