Tính. a) 1/7 + 1/9; 3/11 + 7/12; 13/5 + 7/6 b) 1/4 − 1/9; 2/5 − 1/4; 11/7 − 5/8

Lời giải:

a) $\frac{1}{7}+\frac{1}{9}=\frac{9}{63}+\frac{7}{63}=\frac{16}{63}$

$\frac{3}{11}+\frac{7}{12}=\frac{36}{132}+\frac{77}{132}=\frac{113}{132}$

$\frac{13}{5}+\frac{7}{6}=\frac{78}{30}+\frac{35}{30}=\frac{113}{30}$

b) $\frac{1}{4}-\frac{1}{9}=\frac{9}{36}-\frac{4}{36}=\frac{5}{36}$

$\frac{2}{5}-\frac{1}{4}=\frac{8}{20}-\frac{5}{20}=\frac{3}{20}$

$\frac{11}{7}-\frac{5}{8}=\frac{88}{56}-\frac{35}{56}=\frac{53}{56}$